0
$\begingroup$

I find what seem to be contradictions between the two. "Morlet" defined here, and its Fourier Transform (FT) below it.

  • DFT's imaginary component zeroes with large N, but real part still doesn't turn into a bell
  • $\mathcal{F}(\text{Morlet})$ seems to be the magnitude of the FT, but off in amplitude.

Code: Python -- MATLAB/Octave


enter image description here

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Browse other questions tagged or ask your own question.