# Why use PSD to analyze a signal instead of its Fourier Transform?

Let's imagine I have a perfectly known signal $$s(t)$$ and I want to analyze its frequency components.

I noticed that mostly everyone would use the PSD of $$s(t)$$ to do that, instead of simply use the magnitude of the Fourier transform of $$s(t)$$. Is there a reason for that ?

• You can't "use" the PSD to analyze the frequency components. It is exactly that which you analyze. The Fourier transform is in fact an important way / step in estimating the PSD – so I'm not sure what you're asking here... – Marcus Müller Jun 18 at 8:34