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I am having an issue with the interaction of the Matlab function block in the Simulink with my model block. Below you can also find the picture. I have created a Matlab function with three inputs and 1 output. Since in the MatLab function block, I have solved a differential equation, it has complex expressions in the form of for example.

(exp(sqrt(-a/b)))

This generates the output of complex data types from the function block. When passing this to the integrator which is the input to my plant, I can not run the Simulink due to the error

    "Cannot pass the complex value to non-complex location"

I tried changing the data types of the integrator, then the same thing happens to other blocks in the Simulink. I also tried using absolute values, which of course gives real numbers, but turns out to be a very large number and generates high magnitude. I really need help in solving this issue. Can anyone help me in this/

Thanks in advance.

enter image description here

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  • $\begingroup$ Are these building blocks supposed to be in the time domain or the s-domain? $\endgroup$ – A_A Jun 1 at 10:05
  • $\begingroup$ they are in time domain. But I am wondering the logic behind this question?. Also, plant can be in the form of the transfer function. $\endgroup$ – Prateek Tiwari Jun 1 at 10:20
  • $\begingroup$ The logic behind the question is to clarify if the model expects an s-plane type of variable to be passed around, or if it expects a single or vector of time domain values. Is it possible to talk a little bit more about what is in the plant or function block? Complex numbers are used to express phase differences. If you are passing around only 1 "thing" (time domain), then you are going to have to find a way of combining the two "things" ($\Re(z), \Im(z)$ for some $z$ variable) into one. $\endgroup$ – A_A Jun 1 at 11:15
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The data type of the signal must be fixed in Simulink. Since you use a square root of a real signal, the output will be real if the data is positive, imaginary if negative. Simulink cannot allow that.

The workaround is to use a complex signal and feed it to the square root block. Then the output will always be complex.

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