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I am looking at the video lecture on Kalman Filter. I got some understanding that if the robot moves that we also shift the enviornment belief model accordingly (the same mean amount the robot moved). I am quite confused that why do we move the belief model of the enviornment. The enviornment itself is stationary so if the robot moves the door will remain in place so their distribution should not be shifted. In the following snapshot, the doors are our measurements and we form the belief of where the robot is with respect to the doors. When the robot moves the doors stay stationary. Why do we move the posterior model of as shown in the image below?

enter image description here

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The idea is that the robot is trying to figure out where it is. The only information it can use is:

  1. Its door sensor which says either you're next to a door or you're not next to a door.

  2. Its map of where the doors are.

That's how we go from the "maximum confusion" (uniform) plot to the one with three humps. This uses the first you're next to a door measurement.

Then, the robot knows it moves to the right. Therefore it must update its probability with a similar movement to the right. However, its motion sensors are a little uncertain, so this has the effect of smoothing the three bumps (well, the whole distribution) a little bit. So the three bumps move to the right and they spread out a little.

The peaks of the three spread out humps are still the robot's best guess as to where it is on its map.

Now we get the second you're next to a door measurement. We multiply our prior (the slightly spread out three-humped distribution) with a new three humped distribution (from our known map). The prior second-door location and the map second-door location will align, so that will generate the largest peak.

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  • $\begingroup$ yes i did understand the process. I am only confused on why do we shift or move the probabilities of doors to the right as you mentioned So the three bumps move to the right and they spread out a little. The three bumps define the probability of doors which are stationary. So if robot want to localize itself with respect to the doors the probability of the doors should remain stationary or move left in reference to the robot as robot moved right in reference to the doors. $\endgroup$ – GENIVI-LEARNER Apr 22 at 16:42
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    $\begingroup$ The probability is the probability of where the robot is. Not where the doors are. If the robot moves to the right (with some uncertainty) then the probability also moves to the right (and the uncertainty smooths the prior a little). $\endgroup$ – Peter K. Apr 22 at 17:28
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    $\begingroup$ Ahh makes sense now. I thought the three humps represent where the doors are with respect to the robot. My bad. $\endgroup$ – GENIVI-LEARNER Apr 22 at 17:48

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