# How to find the sampling vector of HD camera recording?

An HD camera records 1080p video (1080*1920, prograssive, 30 frames/sec) wiht croma subsampling 4:2:0 for a total of 90 minutes. The quantizer which is being used for the chroma representation has 256 levels per component (8 bits per component). I want to compute the following:

1. If the dimensions of the sensor that recrods the video are $$\ 3276*5856μm$$, find the sampling vector $$\ T_{3x3}$$ (or grid vector, I don't know exactly the name of that vector) for the initial RGB recording.
2. Compute the compression ration in order to broadcast the video in real time though a channel with $$\ throughput = 2Mbits/sec$$.

I know that the sampling vector for the progressive video has the form:

$$\ T = \begin{matrix} \frac{T_t}{2} & 0 & 0\\0 & T_h & 0\\T_v & 0 & 2T_v \end{matrix}$$

whre $$\ T_t = 1/30$$ for the frames/sec, $$\ T_h$$ is for the horizontal sampling and $$\ T_v$$ is for the vertical sampling. How can I find $$\ T_h, \ T_v$$ for the inital RGB recording ?

About the second question: The size of the whole video is: $$\ size = bitrate \ * \ duration$$ and we can compute both from the given data. The compression ratio is: $$\ ratio = \frac{Uncompressed}{Compressed}$$ where the $$\ Uncompressed = size$$ in bits. With the specific channel, I can send: $$\ 2000000bits/sec$$, so for the whole duration of the video ($$\ 90*60 = 5400 \ seconds$$, I can transmit $$\ total = 2000000*5400 \ bits$$. Is the compression ratio: $$\ r= \frac{size(in bits)}{total}$$ ?