Problem 9.14

I have solved the problem 9.14 in Oppenheim's Signals and Systems textbook, but my solution and the one in Slader is different. Problem is given above. And Slader solution is here.

I have also attached my solution below. Laplace transforms are the same but ROC in the Slader solution and mine is different. My question is how can this Laplace transform have an ROC as Re{s}>0. This should be wrong since this region contains the two poles of the Laplace transform which should not be the case for a rational Laplace transform.

Thanks in advance. enter image description here

  • $\begingroup$ i dunno why, but i almost never worry about ROC regarding the Z Transform (or Laplace) of various functions of time. it's just not all that practically salient to me. $\endgroup$ – robert bristow-johnson Jan 21 at 18:22

You're right, the ROC of the Laplace transform of a two-sided signal is a strip in the complex plane. In your case, the imaginary axis is inside the ROC, and the ROC is limited by the poles in the right and left half-planes. If the ROC were the right half-plane, the signal would be right-sided, which is clearly not the case.

| improve this answer | |

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.