0
$\begingroup$

I read that at the correct sample times of a matched filter output the noise is independent assuming a Nyquist pulse.

Can someone provide a proof of this or explain it more? Assuming your matched filter duration had a longer duration than your sample period, it seems the sample noise should be correlated.

Why is this not the case?

$\endgroup$
  • 1
    $\begingroup$ There's quite a bit of context missing for that statement, it's not generally true. Can you share the full sentence/paragraph this is from? $\endgroup$ – Marcus Müller Jan 4 at 23:11
  • $\begingroup$ Ok, I read as follows: assuming IID additive white gaussian noise the noise output of the matched will be independent when sampled at the correct sampling times(assuming a Nyquist pulse for example). Logically it doesn't seem correct since your matched filters duration will longer than your sample period. $\endgroup$ – FourierFlux Jan 4 at 23:39
  • $\begingroup$ assuming a nyquist pulse is kind of important here. Please edit your question to include the whole paragraph, not just this sentence. $\endgroup$ – Marcus Müller Jan 4 at 23:58

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Browse other questions tagged or ask your own question.