# How to determine sampling frequency for an x(t) signal avoiding aliasing?

The antitransform of the function is given:

$$\hat{x}(f) = \frac{123 + i246\pi f}{246 - 24600 \pi^2 f^2 + i4920\pi f}$$

I'm asked to determine which frequency can I sample using the function x(t) avoiding aliasing? (or which range of values)

Update the problem actually suggest five answers: 100, 10, 1, 0.4 or none of these. Turns out the answer is none of these.

• draw a bode plot for given transfer function and the bandwidth comes close to 0.275 Hz hence sampling frequency is grater than 0.55 Hz, if your calculations is based on cutoff frequency (0.2 Hz) then sampling frequency becomes 0.4 Hz. – Ch.Siva Ram Kishore Dec 12 '19 at 16:47
• “losing aliasing” is a peculiar usage. do you mean avoiding aliasing? – user28715 Dec 12 '19 at 18:08
• @StanleyPawlukiewicz yes, sorry I'm correcting it. – Someone Dec 12 '19 at 18:12

The function you show has a frequency range of $$-\infty$$ to $$\infty$$ so it isn’t strictly band limited. To completely avoid aliasing, it needs infinite sampling.
• How did you determine the frequency was -\infty to \infty – Someone Dec 12 '19 at 18:30
• Probably by inspection. But the formal way to do it is to note that for any finite $f$, $\left | \hat x (f) \right | > 0$. – TimWescott Dec 12 '19 at 18:31