# average power of signal given the mean and the variance [closed]

Let a signal be a random process.Given the mean and variance what is the average power of the signal.

• Hi! why cannot you find it by yourself ? – Fat32 Dec 6 '19 at 19:44

Given the variance of the signal $$x(t)$$, $$\text{var}(x(t))$$, you can express it as:
$$\text{var}(x(t))=E[ x^2(t) ] - E[x(t)]^2$$
$$E[x^2(t)] = \text{var}(x(t)) + E[x(t)]^2 =\sigma_x^2+\mu_x^2$$