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Let a signal be a random process.Given the mean and variance what is the average power of the signal.

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  • $\begingroup$ Hi! why cannot you find it by yourself ? $\endgroup$ – Fat32 Dec 6 '19 at 19:44
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Given the variance of the signal $x(t)$, $\text{var}(x(t))$, you can express it as:

$ \text{var}(x(t))=E[ x^2(t) ] - E[x(t)]^2 $

Rearranging you can get the average signal power:

$ E[x^2(t)] = \text{var}(x(t)) + E[x(t)]^2 =\sigma_x^2+\mu_x^2$

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