Given a signal $r(t)$ which is a result of convolution between signal $x(t)$ and a channel $h(t)$ as below :
$r(t) = h(t)*x(t); $
what I know, the time reversal convolution can be process as follows : $y(t) = r(t)*h^*(-t) = h(t)*x(t)*h^H(-t);$ where * denote to the convolution and $h^H$ is the conjugate. I think that right and clear, but what does mean $h(-t)$. is it all simply equals to $conv(r(t), -h(t))$ for example as below :
x = randn(1,5); h = randn(1,3); r = conv(h,x); y = conv(r,-h);
Is y is correct in the above example? however I think it should be continuous where the above example is discrete signal.