I want to use waverec
to evaluate a linear combination of the scaled and shifted wavelet of the form
$$ \sum_{i=1}^n\sum_{j=0}^{2^n-1}d_{nj} 2^{-n}\psi_{ij} (\frac{t-j}{2^n}) +c_{00}\phi(t) $$ at $t=k2^{-n} $ for $k=0\dots2^{n}-1$. I know how do it for the Haar wavelet, namely
[c,l]=wavedec(zeros(1,8),3,'haar')
waverec(2^(3/2)*[c00 d10 d20 d21 d30 d31 d32 d33],l,'haar')
But how can you do the same thing for Daubechies wavelets? The problem being that the array c
does not have 8 entries but 28:
[c,l]=wavedec(zeros(1,8),3,'db4')
c =
Columns 1 through 14
0 0 0 0 0 0 0 0 0 0 0 0 0 0
Columns 15 through 28
0 0 0 0 0 0 0 0 0 0 0 0 0 0
l =
7 7 7 7 8
The Question is related to Number of Daubechies coefficients, but I do not understand the answer.