I would assume you perform the calculations the same way, but since there would be no imaginary component because the signal is not complex it would be simpler:
magnitude = |x(n)|
power = |x(n)|^2
phase = 0 (for all values of n) - since there's no imaginary portion the phase equation would always result in a 0 value.
I'm trying to fully grasp and internalize some of the basic concepts of signal processing, and while I haven't ever really seen anyone try to use the equation for phase on a time-domain signal I don't see why it wouldn't be valid even if the results don't have much meaning.