I assume $3$ users. In the CDMA, the signals after the spreading for the $3$ users have the same bandwidth $B$.

Is it possible to have $3$ spreading signals of the same band $B'$ such that $3B'=B$? More precisely, the spectrum for the $3$ spreading signals don't overlap but they are in the bandwidth $B$.

  • $\begingroup$ It may be possible, since the chip rate controls the amount of spreading. But, what is the purpose of doing that? You would no longer have CDMA, but a weird variant of FDMA. $\endgroup$ – MBaz Apr 26 at 15:18

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