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What is the relationship to calculate degrees of rotation in the constellation given a baud rate and frequency offset?

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frequency is the derivative of phase over time; phase hence frequency's integral over time. And that's all the knowledge you need, since baudrate gives you the time between consecutive symbols.

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  • $\begingroup$ to measure the phase rotation caused by a given frequency offset across a frame/burst/slot of data, is it fair to say it's not a function of the baudrate but rather the duration of that frame/burst/slot ? The delta t would be the burst duration in that case? $\endgroup$ – BigBrownBear00 Feb 23 '19 at 15:01
  • $\begingroup$ since the baudrate would define the length of a burst, I don't think that is an overly sensible statement, no. $\endgroup$ – Marcus Müller Feb 23 '19 at 18:29
  • $\begingroup$ I believe we are in agreement. Plenty of commercial specs define bursts in terms of duration in seconds. $\endgroup$ – BigBrownBear00 Feb 23 '19 at 19:09

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