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I am currently trying to perform an experiment given an audio signal. I am therefore sampling the audio frequency range (0 to 22kHz) with a 48k sampling rate.

When performing a FFT on my signal, I had the following question :

  • Is it equivalent to have a very small FFT size (for example 256), producing a 172 Hz resolution on my signal, in comparison with having a large FFT size (in a way more bars..) and performing a mean on my resulting frequencies in order to bring the number of bars down?
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  • $\begingroup$ The bin width of the fft is Sampling Frequency/number of samples (Fs/N). Larger fft will help you resolve more. $\endgroup$
    – Vaibhav Garg
    Commented Feb 28, 2019 at 9:17

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The two are not equivalent. Taking a larger FFT means you are using more time domain samples (unless you zero pad), in which case you have introduced new information compared to a smaller FFT size

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