Let $s(t)$ an up-chirp with bandwidth $B$ and $y(t)$ an down-chirp with the same bandwidth. For a multi user chirp spread spectrum (2 users), I use the up-chirp and down-chirp as spreading signal. The system bandwidth is $B_c$ with $B_c=B$.

But if I look at the spectrums for the 2 users, there is no superposition. Consequently, can we transmit these signals because we must have a system bandwidth $B_c$?

  • $\begingroup$ "when I look at two spectra, there is no superposition" <- I don't think I understand what you mean. Can you put this in formulas, or a picture, maybe? $\endgroup$ – Marcus Müller Feb 21 '19 at 19:10
  • $\begingroup$ without a window on the chirp, the bandwidth is arbitrarily wide. $\endgroup$ – robert bristow-johnson Feb 21 '19 at 23:36

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