0
$\begingroup$

enter image description here

Please help me to solve this question.

$\endgroup$

closed as off-topic by Stanley Pawlukiewicz, MBaz, lennon310, A_A, Fat32 Jan 21 at 10:39

This question appears to be off-topic. The users who voted to close gave this specific reason:

  • "This question appears to be homework. Complete answers to homework are off-topic, but specific questions about homework are acceptable if they include enough detail. Please edit the question to include more background about what you don't understand." – Stanley Pawlukiewicz, MBaz, lennon310, A_A, Fat32
If this question can be reworded to fit the rules in the help center, please edit the question.

0
$\begingroup$

When the spectrum is complex conjugate symmetric around $f_s/2$ (and multiples etc.) the corresponding signal is real valued and vice versa.

This holds for your example, meaning your signal should be real-valued. Your phase spectrum is interesting, since zero phase shift in all frequencies means your spectrum is real valued as well.

$\endgroup$
  • 1
    $\begingroup$ Thank you for the answer $\endgroup$ – user170106 Jan 21 at 14:40

Not the answer you're looking for? Browse other questions tagged or ask your own question.