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I have a system $h(t)=4e^{-4(t-4)}u(t-4)$ and I want to response of the system to $x(t)=rect(2(t+4))$. I have followed those steps:

$y(t)=x(t){*}h(t)$

$=rect(2(t+4)){*}4e^{-4(t-4)}u(t-4)$

$=4[u(t)-u(t+8)] { * } e^{-4(t-4)}u(t-4)$

$=4[u(t){*}e^{-4(t-4)}u(t-4)] - 4[u(t+8){*}e^{-4(t-4)}u(t-4)]$

I got stuck after this point. I have an exam in a week. Thanks in advance for the help.

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    $\begingroup$ Now it's time to actually calculate the necessary convolutions by using the definition of convolution for continuous-time signals. What keeps you from doing just that? $\endgroup$ – Matt L. Dec 26 '18 at 13:15

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