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Can you obtain a transfer function in frequency domain with a bode plot form given by this function: $$ S=k1 \sqrt{1+\frac{k2}{f}} $$ I did not managed it because actually in the lowest part of frequencies decreases with 10dB/dec. So is not a simple pole (20dB/dec) and zero function. Maybe it is possible to obtain such function by adding many low pass filters. Any idea?

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  • $\begingroup$ I think maybe you are confused it's already in frequency domain please check it out. $\endgroup$ – Ch.Siva Ram Kishore Dec 25 '18 at 3:53
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    $\begingroup$ These questions are related and may be helpful: Q1, Q2, Q3 $\endgroup$ – Matt L. Dec 25 '18 at 9:48
  • $\begingroup$ @Ch.SivaRamKishore The purpouse is to obtain a transfer function with a form similar to the plot of S(f). Off course, the S is dependent by the frequency but not expressed in term of s. $\endgroup$ – Ba5o Dec 27 '18 at 16:49
  • $\begingroup$ Glad to have provided the correct answer to this ghosted question. $\endgroup$ – Ed V Mar 16 '20 at 23:16
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The objective is to produce noise, presumably Gaussian distributed, that has both white and 1/f components. This is evident from the desired power transfer function, i.e., the square of the OP's "S" expression, which would be used to convert input white noise to output white plus 1/f noise. The OP does not state whether the PSD should be unilateral or bilateral, so it will be assumed, without loss of generality, to be unilateral. Hence the unilateral noise PSD is

$$\mathrm{S^2 = k_1^2(1+k_2/f)} \tag{1}$$

where $\mathrm{k_1^2}$ is the unilateral noise PSD of white noise only, with units of $\mathrm{V^2/Hz}$ and $\mathrm{k_2}$ is the noise corner frequency, with units of $\mathrm{Hz}$. In a digital simulation,

$$\mathrm{k_1^2} = 2\sigma^2 /f_s = \sigma^2 /f_{nyquist} = 2\sigma^2 \times \Delta t \tag{2}$$

where $\sigma$ is the standard deviation of the Gaussian white noise (units: V), $\mathrm {f_s}$ is the constant sampling frequency (units: Hz), $\mathrm {f_{nyquist}}$ is the Nyquist frequency (units: Hz), and $\mathrm {\Delta t}$ is the constant sample time spacing (units: s).

To generate the noise, first select parameters in accordance with equation 2. For example, if it is desired to have $\mathrm{k_1^2} = 5.00 \times 10^{-8}$ $\mathrm{V^2/Hz}$ and $\mathrm {f_s} = 1$ $\mathrm{kHz}$, then $\sigma = 0.005$ $\mathrm{V}$. This is the standard deviation entered into the Gaussian white noise generator in the figure below:

Simulation model

The second step is to specify $\mathrm{k_2}$. Using the noise generator described previously here, it is not feasible to directly enter a noise corner frequency into the non-white noise generator code. However, it is necessary to enter the desired low limit and high limit for the non-white noise, as shown in the dialog box in the figure, so the high limit can be adjusted empirically to obtain the desired noise corner frequency. Note that $\gamma = 1$ generates $\mathrm{1/f}$ noise and there is an optional gain adjustment as well.

The next figure shows a temporal trace of the noise produced with $\mathrm{k_1^2} = 5.00 \times 10^{-8}$ $\mathrm{V^2/Hz}$, $\mathrm {f_s} = 1$ $\mathrm{kHz}$, $\sigma = 0.005$ $\mathrm{V}$ and the non-white noise parameters shown in the first figure:

Noise temporal waveform

Then the third figure shows the average of 1000 32k FFT PSDs:

Noise PSD

The noise corner frequency is where $\mathrm{f = k_2}$. From the plot, this is about 1.6 Hz or so.

If this noise was the dominant one in an experiment, and if the signal was baseband, then the measurement would be afflicted with $\mathrm{1/f}$ noise and all the annoying consequences that entails. But if it was feasible to modulate production of the signal, before the signal encountered the noise, then the signal could be deliberately located in the white noise 'flats' and a lock-in amplifier could perform the customary demodulation.

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