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I am studying radix 2 algorith from Proakis' book.

But I'm a bit confusied why 1st DFT $G_1$ is not multiplied by complex entity while 2nd DFT $G_2$ is being multiplied by complex entity $W$ as shown highlighted in attached figure.

enter image description here

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    $\begingroup$ Hi! Have you tried wiriting the DFT of x[n] by dividing it into even and odd sampled sequences g1[n] and g2[n] ? The weight will come from that DFT. $\endgroup$ – Fat32 Dec 2 '18 at 17:48
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Now as the document says, let $x[n]$ be a length $N$ (even) sequence whose even and odd indexed samples are denoted as $g_1[n]$ and $g_2[n]$ of length $N/2$ each.

Then the $N$-point DFT $X[k]$ of $x[n]$ can be written as folows:

$$\begin{align} X[k] &= \sum_{n=0}^{N-1} x[n] e^{ -j \frac{2\pi}{N} n k} ~~~,~~ k = 0,1,...,N-1 \\\\ &= \sum_{n=0,2,4}^{N-1} x[n] e^{ -j \frac{2\pi}{N} n k} + \sum_{n=1,3,5}^{N-1} x[n] e^{ -j \frac{2\pi}{N} n k}\\\\ &= \sum_{m=0}^{N/2-1} x[2m] e^{ -j \frac{2\pi}{N} 2m k} + \sum_{m=0}^{N/2-1} x[2m+1] e^{ -j \frac{2\pi}{N} (2m+1) k}\\\\ &= \sum_{m=0}^{N/2-1} g_1[m] e^{ -j \frac{2\pi}{N/2} m k} + e^{ -j \frac{2\pi}{N} k} \sum_{m=1}^{N/2-1} g_2[m] e^{ -j \frac{2\pi}{N/2} m k} \\\\ &= \left( \sum_{m=0}^{N/2-1} g_1[m] e^{ -j \frac{2\pi}{N/2} m k} \right) + e^{ -j \frac{2\pi}{N} k} \left( \sum_{m=1}^{N/2-1} g_2[m] e^{ -j \frac{2\pi}{N/2} m k} \right) \\\\ &= G_1[k] + W_N^k G_2[k] ~~~,~~ k = 0,1,2...,N-1 \\ \end{align}$$

Where we have recognized the summations inside the parenthesis as the $N/2$ point DFTs of the sequences $g_1[n]$ and $g_2[n]$ respectively. Note that when $k$ spans the range $k=0,1,...,N-1$, the $N/2$ point DFTs will repeat twice.

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