# Calculating fourier transform

I have just recently started doing fourier transforms and I'm a little confused.

Can someone walk me through in detail how to calculate the Fourier transform of

I'm not looking for answer, just an explanation of how to go about doing it.

• so you $y(t)$ is just $y(t) = \sin (2\pi f t)$. I'm sure you can find a) an entry in your Fourier transform table for that, and if that's not your goal, remember that $\sin x = \frac1{2i}\left(e^{ix}-e^{-ix}\right)$. Generally it's a bit unclear from which background you're approaching this, so, an explanation of what you've considered so far might be helpful! – Marcus Müller Nov 17 '18 at 18:51

• you need to use $\LaTeX$ instead of graphics for equations. and your integrals lack the $dt$ on the right. – robert bristow-johnson Nov 21 '18 at 6:34
In case of an aperiodic signal, say a decaying exponential $$x(t) = e^{-5t}u(t)$$, its Fourier transform can be evaluated as:\ $$\begin{eqnarray} X(j\omega) &= \int \limits_{-\infty}^{+\infty}e^{-5t}u(t)e^{-j\omega t}dt &\\ &= \int \limits_{0}^{+\infty}e^{-(5+j\omega)t}dt &\\ &= \dfrac{1}{5+j\omega} & \end{eqnarray}$$