For two processes $X(t)$ and $Y(t)$, PSD of $Z(t) = X(t) + Y(t)$ is $S_Z(\omega) =S_x(\omega)+ S_Y(\omega) + S_{XY}(\omega)+S_{YX}(\omega) $.

If $X(t)$ and $Y(t)$ are orthogonal, PSD of the sum process is sum of the PSDs of individual processes. However for correlated processes, an additional PSD term comes into picture. What is the physical significance of this behavior? To be more specific, the resulting PSD is greater than the sum of individual of PSDs.How can we explain this behavior qualitatively?

  • 2
    $\begingroup$ look at the case that $X(t) = Y(t)$ ... $\endgroup$ – AlexTP Oct 23 '18 at 18:50
  • $\begingroup$ Even better: look at $X(t) = -Y(t)$ $\endgroup$ – Hilmar Oct 23 '18 at 23:28

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Browse other questions tagged or ask your own question.