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Here is the trapezoid wave,although i know we can use $\int^{4}_0 |x(t)|^2dt$ to calculate its power,but i want to divide this trapezoid to right triangle$(t=0$~$2)$,and a square ($(t=2$~$4)$).

I know the the triangle effective voltage is $V_{eff}=\frac{V}{\sqrt{3}}$,and i want to use $P=\frac{V_{eff}^2}{R}$ to calculate the power , but i am not sure about which triangle is correct,i mean,for which triangle(a or b or c),i can use $\frac{V}{\sqrt{3}}$ to calculate its power,or are these three wave's power the same,but different in energy?

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    $\begingroup$ seems to me that you must "simply" apply the definition. can you integrate functions? $\endgroup$ – robert bristow-johnson Sep 14 '18 at 18:46
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it seems that there power are the same,but there energy are not the same ,because energy=power $\times$ time,and time are different,so their energy are not the same too

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  • $\begingroup$ no, that can't be. Same signal power and same duration means same energy, so something in your calculation must be wrong. $\endgroup$ – Marcus Müller Dec 16 '18 at 14:53

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