0
$\begingroup$

enter image description here

Here is the trapezoid wave,although i know we can use $\int^{4}_0 |x(t)|^2dt$ to calculate its power,but i want to divide this trapezoid to right triangle$(t=0$~$2)$,and a square ($(t=2$~$4)$).

I know the the triangle effective voltage is $V_{eff}=\frac{V}{\sqrt{3}}$,and i want to use $P=\frac{V_{eff}^2}{R}$ to calculate the power , but i am not sure about which triangle is correct,i mean,for which triangle(a or b or c),i can use $\frac{V}{\sqrt{3}}$ to calculate its power,or are these three wave's power the same,but different in energy?

enter image description here

Improve this question
$\endgroup$
1
  • 1
    $\begingroup$ seems to me that you must "simply" apply the definition. can you integrate functions? $\endgroup$ – robert bristow-johnson Sep 14 '18 at 18:46
-1
$\begingroup$

it seems that there power are the same,but there energy are not the same ,because energy=power $\times$ time,and time are different,so their energy are not the same too

Improve this answer
$\endgroup$
1
  • $\begingroup$ no, that can't be. Same signal power and same duration means same energy, so something in your calculation must be wrong. $\endgroup$ – Marcus Müller Dec 16 '18 at 14:53

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.