0
$\begingroup$

In wikipedia, there was an example on QPSK modulation where the main signal was 11000110 and I contained 1001 and Q contained 1010, now their output was shown by the Signal in the figure.

Time diagram of QPSK

Now according to constellation diagram Signal can be represented as 

11 -> pi/4                           
00 -> -(3*pi)/4                           
01 -> (3*pi)/4                            
10 -> -pi/4

enter image description here

But my confusion was in the phase vs time diagram shown in another figure given below

enter image description here

For 11 it starts from phase pi/4, but for 00 shouldn't the phase start from -(3*pi)/4 = -135 ?

Improve this question
$\endgroup$
1
  • $\begingroup$ Um, I'm not sure I understand what you're asking here. Are these diagrams linked? The mapping of bit groups to constellation points is arbitrary (in reality, gray coding puts a restriction to arbitrarity). $\endgroup$
    – Marcus Müller
    Aug 31, 2018 at 6:56

1 Answer 1

Reset to default
1
$\begingroup$

You're right that the phase plot doesn't match the signal plot. Note that it also shows more symbols than the signal plot. Those two plots do not refer to the same bit sequence, and the phase plot is only meant to illustrate the difference between QPSK and OQPSK (the original figure consists of two plots, one for QPSK and one for OQPSK).

Improve this answer
$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge that you have read and understand our privacy policy and code of conduct.

Not the answer you're looking for? Browse other questions tagged or ask your own question.