Maybe this a stupid question, but I came along with this point and I would like to confirm that I am not wrong.
I found some similar posts in StackExchange, like:
In one of the answer, it is stated "as S(t) is determistic[...]" and then the deterministic signal is taken out of the expectation.
and we know that for instance if I have a constant value, I can take it out of the Expectation operator, e.g.:
Where lambda is a random variable and "a" is a constant. Ok, so, if "a" is a constant, then fair enough, but what happens when "a" is a deterministic signal, but it is not a constant, for instance, what happens if "a" is a squared subcarrier?
Can I still safely say that the expectation will be the product of the deterministic signal multiplied by the expectation of the random variable?