Is it true that in the Range Migration Algorithm for synthetic aperture radar, the azimuth extent can be said to span the length of the flight path?

This makes sense but also does not make sense. Because what if the scene being imaged is 1 km, then won't the flight have to travel a ridiculously long extent?


So in the final step of the RMA, an inverse FFT is taken on a phase that has the form (after stolt interpolation): $ \phi(K_X, K_R) = -K_XX_t + K_Y(R_B-R_S)$


$K_X = azimuth\ spatial\ frequency\ \epsilon\ [\frac{-\pi}{\Delta X}, \frac{\pi}{\Delta X}] $

$K_Y = ground\ range\ direction\ frequency\ $

$X_t = scatterer\ azimuth\ location$

$R_B - R_S = scatterer\ ground\ range\ displacement$

After this step, my question is what the span of $X_t$ would be. i.e. how to calculate the azimuth axes.

  • $\begingroup$ I think a quick hand drawing will go a looooong way here :) But, yeah I think you're right, but I'm not sure I 100% accurately understand you. $\endgroup$ Commented Jun 28, 2018 at 8:58
  • $\begingroup$ thanks! i have clarified the portion of the rma equation that is not clear at this point $\endgroup$
    – matthew
    Commented Jun 29, 2018 at 0:37

1 Answer 1


I'm going to assume that you are operating in Stripmap mode with no squinting i.e. broadside mode. The aperture size is given by the real antenna azimuth beamwidth (in radians) times the range to the target. What you use as the beamwidth is really a design question - you can use 3dB point or the null-null width. The beamwidth will also be affected by the elevation beampattern somewhat.

You can see near range targets will have a smaller synthetic aperture and thus have smaller coherent gain ( fewer azimuth pulses that can be coherently added). Farther range targets will have a larger coherent gain because more pulses can be coherently added. Most SAR systems have a relatively small range swath widths and so the change in the aperture length is pretty small. The beamwidth is what limits the extent of the azimuth Doppler freqency and thus determines the azimuth resolution.

There are a couple of approaches to handling larger range swath widths. The problem with large range swath widths has more to do with handling the change in range curvatures over the range swath rather than the change in the aperture length. One of the better books to discuss this is by Cumming and Wong:"Digital Processing of Synthetic Aperture Radar Data"

Note that in practical processing systems - if the synthetic aperture at your range of interest contains N pulse, you tend to process much more than N pulses so that you get more azimuth data at the output of your processing. If you only process N pulses - then you get 1 point in azimuth, while if you process 2N pulses you can process N+1 synthetic apertures (1->N,2->N+1, ...,N+1->2N) and you get more effective processing.

In Spotlight mode you steer the antenna beam at one spot on the ground throughout the data collection. This allows a higher-resolution image to be formed but over a smaller area.


Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.