# Signal analysis using a buffer [closed]

I am performing an analysis of an output signal in the interval $t<0$ from the operational amplifier given in the following image

where $v_{C_1}(0^-)$ and $v_{C_2}(0^-)$ are the initial conditions to be computed of two capacitors. As you can see, the solution is just below the image.

What I can't understand is why all the measured voltages are $1V$ without knowing the values of the resistances and just knowing that $V_-=V_+$. For sure I am missing something that I don't know. Can someone give me a hint? Thank you.

• That's not really a signal proc question, more of a "basics of the three golden opamp rules" question... (Hint: three golden rules. Apply them. Commented Jun 20, 2018 at 17:32
• @MarcusMüller I would post it in electronics stack exchange but you don't know how mean the people is there. Ok, with that said my problem is solved: The inputs draw no current. Thank you good sir! Commented Jun 20, 2018 at 17:36
• I'm one of the people over there. We try hard to not be mean :( Commented Jun 20, 2018 at 20:57
• I'm voting to close this question as off-topic because this is a circuit analysis question, not a SP question.
– MBaz
Commented Jun 20, 2018 at 21:37