The least square solution is strictly convex. So you only have one minimum, although in cases, several combinations of inputs yield the same minimum.
Let us go back to a simpler situation: assume that you are given two numbers, $a$ and $b$, what is their best estimate? "Best" requires some more information:
- How best (distance)?
- What do variables relates (model)?
- Where do $a$ and $b$ dwell (probability)?
If how best is a least-squares error loss function, a quadratic measure can be minimized. If the model is a polynomial function, its degree should be fixed). If $a$ and $b$ have known properties, they should be assumed.
The case of constant zero values renders most loss functions useless and reduces the space of variation to nil. In other words, if $a$ and $b$ are equal, and you don't did fancy behavior, one answer is, for any $\alpha$,
$$ \alpha a + (1-\alpha)b$$
but you could as well:
$$ (a^\alpha b ^ \beta)^{\frac{1}{\alpha+\beta}}$$
and many others, depending on the model you wish.
So, the proper "best estimate" is either:
- totally determined by your deterministic situation, and you ought to check input values and determine a predefined output based on logical testing (not based on stochastic optimization)
- set by "other" rules, imposed on the model ( sparse model on, $\alpha$ or $\beta$ for instance), that can give you a more "singular" solution.
So, in your case, the simplest model could be a solution. So what's the simplest?