I am new to EE area and I met a question in my homework:
Can someone help me a little bit? I think it is quite easy!
Thanks!!
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3$\begingroup$ It means they can take complex values. $\endgroup$– MBazCommented Sep 21, 2017 at 1:11
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2$\begingroup$ @MBaz, Short answers are still answers :) (This question cannot be closed as off-topic, unclear or too-broad, so if not closed as answered it will be circulating for ever :/ ). $\endgroup$– A_ACommented Sep 21, 2017 at 8:54
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$\begingroup$ @A_A I hope you don't mind: I edit your comment to link to meta. :-) $\endgroup$– Peter K. ♦Commented Sep 21, 2017 at 12:52
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$\begingroup$ @A_A I didn't put it as an answer since I thought I had misunderstood the question :) $\endgroup$– MBazCommented Sep 21, 2017 at 13:18
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1 Answer
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It means that $x(n)$ and $y(n)$ can be complex numbers rather than just real numbers. As a result there is no conjugate symmetry in the Frequency domain for these signals. Note that part (c) the asterisk in $x^*(n)$ usually means to take the complex conjugate. If $x(n)$ and $y(n)$ were real, i.e. not complex, then (b) and (c) would be equivalent.
