2
$\begingroup$

For M-QAM modulation, where e.g. $M = 64$ there are 8 amplitude levels. Each level is represented by a symbol that is further represented by bits through the relation: $$b=\log_2(M)$$ This means that each symbol is encoded by $b$ bits.

  • I don't quite understand where 64 comes. Does it mean that the imaginary and real component are included ($8\cdot 8$) ?
  • For other modulation methods such as 16-QAM, where is the 16 coming from?
$\endgroup$

1 Answer 1

3
$\begingroup$

There are $M$ symbols in an $M$-QAM constellation where two carriers I and Q are amplitude modulated, and there are $N=\sqrt M$ amplitudes for each I and Q carriers (for $M\ge4$). In $16$-QAM there are 16 symbols on a $4\times4$ constellation. That is, there are $4$ amplitude levels for the I and $4$ levels for the Q component. Of course, $\log_2M$ bits are conveyed by each symbol. Since $M$-QAM normally uses carriers with symmetric amplitudes, $M$ is usually a power of $4$. For instance, $M$ can be $4, 16, 64, 256,\cdots$.

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge that you have read and understand our privacy policy and code of conduct.

Not the answer you're looking for? Browse other questions tagged or ask your own question.