0
$\begingroup$

enter image description here

Okay so i understand the first det, which is why i got the correct solution. However for the second det, im not sure how to solve it since because of the different coefficents (0,2,4) and i tried of different solutions. If anyone can give me a clear way to solve these it would be appreciated. Thank You.

$\endgroup$
  • 1
    $\begingroup$ this is a math, but not, as is, a signal processing question, and thus, off-topic here. $\endgroup$ – Marcus Müller Jun 7 '17 at 22:19
2
$\begingroup$

If you open the determinants along the middle column, we get for the first determinant:

$ -(bf-ec) + (af-cd) -(ae-bd) = -3$ $\hspace{1cm}$ $ [1]$

And for the second determinant, we get

$-(bf-ec) + 2(af-cd) -3(ae-bd) = -2 $ $\hspace{1cm}$ $ [2]$

The required determinant is

$ 2(af-cd) -4(ae-bd) $ $\hspace{1cm}$

Which is just $2*([2] - [1])$, which boils down to $2$.

$\endgroup$

Not the answer you're looking for? Browse other questions tagged or ask your own question.