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According to the Paley-Wiener criterion, a system is causal if satisfies:

$$\int\limits_{-\infty }^{+\infty }{\frac{\ln (|H(f)|)}{1+{{f}^{2}}}}df<\infty$$

So I want to know

  1. This equation is related to LTI system only?
  2. Only casual system is realizable?for linear and non-linear systems?
  3. Which kinds of systems can we create?(only Paley-Wiener criterion can be enough?)
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    $\begingroup$ Oh. Seriously. When I said "please don't ask THREE unrelated questions in one question", I did NOT mean to say "ask TWO totally unrelated questions in one question" $\endgroup$ Commented Nov 20, 2016 at 15:41
  • $\begingroup$ I'm voting to close this question as off-topic because OP asks two completely unrelated questions in one question. $\endgroup$ Commented Nov 20, 2016 at 15:42
  • $\begingroup$ also, this is not even just two questions; in fact, the first two "?" seem to belong to two totally unrelated topics. $\endgroup$ Commented Nov 20, 2016 at 15:43
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    $\begingroup$ @MarcusMüller, instead of being so agressive, you should guide the OP to conduct their concerns. It is very simple to be ironic on other mistakes. We all know you have high rep. $\endgroup$
    – Brethlosze
    Commented Nov 21, 2016 at 4:50
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    $\begingroup$ this question should be re-opened. $\endgroup$ Commented Nov 21, 2016 at 6:19

1 Answer 1

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The Paley-Wiener criterion defines a condition on the magnitude spectrum of a causal time-domain function. So if the Paley-Wiener criterion is satisfied for a given $A(\omega)=|H(\omega)|$, we know that there is a causal function with magnitude spectrum $A(\omega)$. It should be noted that the Paley-Wiener criterion is only applicable to square-integrable functions $A(\omega)$. If $A(\omega)$ is not square-integrable then the criterion is neither necessary nor sufficient.

A frequently occurring misunderstanding is that, given a frequency response $H(\omega)$, we can check the causality of the corresponding system using the Paley-Wiener criterion. This is generally not the case. If the criterion is not satisfied we know for sure that $H(\omega)$ is not the frequency response of a causal system. But if it is satisfied we only know that there must be a causal function with magnitude spectrum $A(\omega)=|H(\omega)|$, but we still don't know if the given $H(\omega)$ corresponds to a causal system. This depends on the phase of $H(\omega)$, and the only thing we know is that it is possible to find a phase response $\phi(\omega)$ such that $H(\omega)=A(\omega)e^{j\phi(\omega)}$ corresponds to a causal system.

To answer your questions:

  1. Yes, it only applies to LTI systems because only LTI systems are fully characterized by a frequency response.
  2. Yes, only causal systems can be realized because we cannot look into the future.
  3. This question is a bit broad. There are realizability conditions for certain restricted sets of systems (e.g., passive LTI systems), but in general, causality is definitely a necessary condition. However, for the above mentioned reason we cannot just take a given $H(\omega)$, check the Paley-Wiener criterion and conclude that we can realize $H(\omega)$ as a causal system, because we didn't take into account the system's phase.
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  • $\begingroup$ Nice answer(+1)! Do you know a good source on Paley–Wiener theorem? And maybe related criterions. $\endgroup$
    – S.H.W
    Commented Oct 14, 2020 at 14:18
  • $\begingroup$ @S.H.W: A good source (in general) is the textbook "The Fourier Integral and its Applications" by A. Papoulis. $\endgroup$
    – Matt L.
    Commented Oct 14, 2020 at 17:48
  • $\begingroup$ Thank you so much for your suggestion. $\endgroup$
    – S.H.W
    Commented Oct 14, 2020 at 18:01

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