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I read the following here. Can someone explain/elaborate on this?

Squaring the signal effectively demodulates the input by using itself as its own carrier wave. This means that half the energy of the signal is pushed up to higher frequencies and half is shifted down toward DC

I didn't find any good source giving more information or examples of this.

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  • $\begingroup$ Please see this link. It's a standard technique for amp.Demod. $\endgroup$
    – A_A
    Jul 15, 2016 at 9:08

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If $m(t)$ is the message signal with $|m(t)|<1$, the AM signal can be written as

$$s(t)=(1+m(t))\cos(\omega_ct)\tag{1}$$

where $\omega_c$ is the carrier frequency in radians per second. Squaring $s(t)$ gives

$$s^2(t)=(1+m(t))^2\cos^2(\omega_ct)=(1+m(t))^2\frac12(1+\cos(2\omega_ct))\tag{2}$$

Low pass filtering $(2)$ gives

$$x(t)=\frac12(1+m(t))^2\tag{3}$$

from which the message $m(t)$ can be retrieved:

$$m(t)=\sqrt{2x(t)}-1\tag{4}$$

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  • $\begingroup$ @Ojtwist: If this answer is helpful, please accept it by clicking on the check mark to its left. Otherwise, you can leave a comment asking for clarification. $\endgroup$
    – Matt L.
    Jul 17, 2016 at 9:33

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