First I would recommend filling in the contour of the toy - in case it looks like the one in the second image. You could do this by analyzing the hierarchy output from findContours: make white all regions having a parent or by using an iterative morphological operations (not directly implemented in OpenCV).
Once the toy is nice and fat (not just the edge), you can remove the cord. I would use here some erosion with a flat kernel (horizontal line).
See the code below (this is in Python, but you'll have a clear overview):
import cv2
lemBGR = cv2.imread("lem.png")
lem = cv2.cvtColor(lemBGR,cv2.COLOR_BGR2GRAY)
# Dilate the image in order to close any external contour of the leming
kernel = cv2.getStructuringElement(cv2.MORPH_ELLIPSE,(5,5))
lem = cv2.dilate(lem,kernel)
# Identify holes in the leming contour
# This could be done by iterative morphological operations,
# but this is not directly implemented in OpenCV
contour,hier = cv2.findContours(lem.copy(),cv2.RETR_CCOMP,cv2.CHAIN_APPROX_SIMPLE)
# And fill them
for c,h in zip(contour, hier[0]):
if h[3]!=-1:
cv2.drawContours(lem,[c],0,255,-1)
# Now bring the leming back to its original size
lem = cv2.erode(lem,kernel)
# Remove the cord by wiping-out all vertical lines
kernel = cv2.getStructuringElement(cv2.MORPH_RECT,(15,1))
#lem = cv2.erode(lem,kernel) # first wipe-out
#lem = cv2.dilate(lem,kernel) # then bring back to original size
# erode and then dilate is the same as opening
lem = cv2.morphologyEx(lem,cv2.MORPH_OPEN,kernel)
# Find the contour of the leming
contour,_ = cv2.findContours(lem.copy(),cv2.RETR_EXTERNAL,cv2.CHAIN_APPROX_SIMPLE)
# And draw it on the original image
for c in contour:
# enter your filtering here
x,y,w,h = cv2.boundingRect(c)
cv2.rectangle(lemBGR,(x,y),(x+w,y+h),(0,255,0),2)
# Display the result
cv2.imshow("lem",lemBGR)
cv2.waitKey()
cv2.imwrite("lem-res.png",lemBGR)
And below are my results.