I need help understanding how/what does it mean to "turn" a transformation parameters into a vote. I know how to recover the transformation parameters (in my case: 6 DOF), but how this turns into a vote in 6D (??) space ?
Thank You !
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A(one dimension for each DOF) where each dimension has the size range/accuracy for the current DOF. This array is your Hough Space.
v = [DOF1, DOF2, DOF3, DOF4, DOF5, DOF6]increment the bin in
vfalls. You have now turned this single vector of transformation parameters onto a vote in the Hough Space,
x is in the range [1;6] and
y also in the range [1;6].
x should be found with an accuracy of one whereas
y only needs an accuracy of two.
A(x,y) looks like this:
where the bold bin corresponds to
So if you would like to cast a vote for a vector
v(x,y)=[3,1] you would simply increment the bold zero by one. Votes for
v(x,y)=[3,2] would in this case fall in the same bin, because of the reduced accuracy needed for
y, whereas votes for
v(x,y)=[3,3] would go into the bin to the right.
I hope this was helpful, and did not just confuse you more. ;)