1
$\begingroup$

Ladies, Gentlemen, Because I am homeless (in France), and get internet access only in public libraries with many restrictions in timing etc, I can not write down even a simple convolution. So I ask you post here the convolution of some sinusoidal function with itshelf.

For example: 0.951056516295, 0.587785252292, -0.587785252292, -0.951056516295, 0.

Regards

$\endgroup$
2
  • $\begingroup$ that doesn't look like a sinusoid $\endgroup$ Nov 18 '15 at 14:52
  • $\begingroup$ Can you convince the library to install a program such as SciLab on their computers? It is free, and its development is supported by INRIA. Having access to such a tool would be very helpful in your research. See scilab.org $\endgroup$
    – MBaz
    Nov 18 '15 at 18:07
1
$\begingroup$

For your data points I get:

-2.467162e-16 -9.045085e-01 -1.118034e+00 7.725425e-01 2.500000e+00 7.725425e-01 -1.118034e+00 -9.045085e-01 -1.480297e-16

from

#27154    
data <- c(0.951056516295, 0.587785252292, -0.587785252292, -0.951056516295, 0.) 
output <- convolve(data,data, type ="open")
$\endgroup$
1
  • 1
    $\begingroup$ Mr Peter K., many thanks for your immediate response. My output agree with yours. Indeed -2.467162e-16 and -1.480297e-16 are zeros. Regards $\endgroup$ Nov 18 '15 at 15:36
1
$\begingroup$

I sent my question from municipal library of saint Claude, France where they offered me just one hour. ow I am in CCAS of the same town where they offer more time, so I will try answer my question.

1) 0.951056516295x0=0 + 0.587785252292x0=0 + -0.587785252292x0=0 + -0.951056516295x0=0 + 0x0.951056516295=0

total = 0

2) 0.951056516295x0=0 + 0.587785252292x0=0 + -0.587785252292x0=0 + -0.951056516295x0.951056516295=-0.9045084971871816 + 0x0.587785252292=0 total = -0.9045

3) 0.951056516295x0=0 + 0.587785252292x0=0 + -0.587785252292x0.951056516295=-0.559 + -0.951056516295x0.587785252292=-0.559 + 0x-0.587785252292=0

total = -1.118

4) 0.951056516295x0=0 + 0.587785252292x0.951056516295=0.559 + -0.587785252292x0.587785252292=-0.3454915 + -0.951056516295x-0.587785252292=0.559 + 0x-0.951056516295=0

total = 0.7725

5) 0.951056516295x0.951056516295=0.9045 + 0.587785252292x0.587785252292=0.3454915 + -0.587785252292x-0.587785252292=0.3454915 + -0.951056516295x-0.951056516295=0.9045 + 0x0=0

total = 2.5

6) 0x0.951056516295=0 + 0.951056516295x0.587785252292=0.559 + 0.587785252292x-0.587785252292=-0.3454915 + -0.587785252292x-0.951056516295=0.559 + -0.951056516295x0=0

total = 0.7725

7) 0x0.951056516295=0 + 0x0.587785252292=0 + 0.951056516295x-0.587785252292=-0.559 + 0.587785252292x-0.951056516295=-0.559 + -0.587785252292x0=0

total = -1.118

8) 0x0.951056516295=0 + 0x0.587785252292=0 + 0x-0.587785252292=0 + 0.951056516295x-0.951056516295=-0.9045 + 0.587785252292x0=0 + -0.587785252292x0=0 + -0.951056516295x0=0 + 0x0=0

total = -0.9045

9) 0x0.951056516295=0 + 0x0.587785252292=0 + 0x-0.587785252292=0 + 0x-0.951056516295=0 + 0x0=0

total = 0

output: 0, -0.9045, -1.118, 0.7725, 2.5, 0.7725, -1.118, -0.9045, 0.

Regards

$\endgroup$
1
  • $\begingroup$ Interesting is 5th summation for samples multiplied themselves (are squared) and sum gets maximum (2.5). Regards $\endgroup$ Nov 19 '15 at 7:43

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.