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The BER is the average number of errors that would occur in a sequence of $n$ bits. When $n = 1$, we can think of the BER as the probability that any given bit will be received in error. Basically, it lies between 0 and 1 --

  • when BER = 0, we can say no error in the received bits.
  • If at least one error is seen, we can say with 100 percent certainty that the BER is definitely not zero.
  • as long as at least one bit was successfully received, we can state that the BER is most definitely less than 1.

When we measure the performance of a digital communication system with and without equalization, with that of the theoretical BER for a particular kind of modulation, we prefer the simulation to be exact match with the theoretical. My Questions are :

(1) Is theoretical BER the upper or lower performance bound?

(2) Is it desired that the BER tends to zero? Is it reasonable to say that since this may not happen in real communication, so there is always a quest to come up with an equalizer designed with an objective that the BER tends to zero?

(3) What if the simulation curve with and without equalizer falls below the theoretical? What can be said about the equalization method playing a role and if it is desired that the simulation curve - with and without equalizer is below the theoretical.

(4) What can be said about performance of the system with and without equalizer if the simulated BER is above the theoretical?

(5) Does an equalizer essentially help to improve the BER? By improving -how much improvement is desired? Tradeoff? Do we wish the simulated curve to be an exact match to the theoretical and then say that the equalizer is functioning properly in removing intersymbol interference and noise?

ber

What is the interpretation for the bit error performance?

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  • $\begingroup$ Are you comparing simulation, with and without equalizer, to theory, also with and without equalizer? If not, then please clarify what you're trying to compare. $\endgroup$ – MBaz Oct 28 '15 at 0:40
  • $\begingroup$ Clarified the Question. Would prefer answers for with and without equalizer case $\endgroup$ – Ria George Oct 28 '15 at 0:49
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Note: usually, the "theoretical BER" is called $P(e)$, the probability of bit error (sometimes with other symbols, like $P_b$). A rate implies experiment; the probability implies theory.

1) $P(e)$ is a lower bound for the BER: since practice is messier than theory, the BER will be higher than $P(e)$ (assuming the theory is correct; that is, that it models reality properly).

2) I'm not sure I understand the question. We always want $P(e)$ to be as low as possible, but it is ultimately bounded by the channel capacity.

3) If by "below the theoretical" you mean "better than $P(e)$", I'd say something is wrong with your simulation or your assumptions.

4 and 5) You use an equalizer when you have a wideband channel with intersymbol interference. Such a system will always have worse BER than a narrowband channel. The equalizer tries to eliminate the ISI; if the equalizer is perfect, the BER of the wideband system will be the same as that of a narrowband channel, assuming equal $E_b/N_0$. In practice, the equalizer will not be perfect. In this case, theory can help predict the equalizer's performance, and how much BER improvement to expect.

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  • $\begingroup$ Thank you for your reply. I have got a graph for BER vs SNR and would appreciate your help in telling me what can be inferred about the performance of the equalizer looking at the simulated ber curve. The simulated curve has ber = 0 at high snr and so taking the log gives -infinity. Thus, there are no values at those points. Is it desired that the simulate BER curve has a smooth profile and does not end at a high bit error rate value in the log scale even though none of the bits are in error at high snr? $\endgroup$ – Ria George Oct 29 '15 at 19:58
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    $\begingroup$ If the BER is zero, it means you're not simulating a large enough number of bits. If you expect, say, a BER of around $10^{-6}$, you should simulate transmission of at least 100 million bits or so. $\endgroup$ – MBaz Oct 29 '15 at 20:54

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