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The passband signal $\ u_p(t) = I_{[−1,1]}(t) \cos 400πt $ is passed through an LPF as $\ u_p(t) \cos(401\pi t).$ The question is to find the output. The example does the following:

If we let $\ u_1 = u_{c1} +ju_{s1} $ denote the complex envelope with respect to the reference $\ e^{j401t} $, the output of the LPF is $\ u_{c1}/2.$ Why is it half?

The passband signal can be rewritten as, $\ u_p(t) = \Re(I_{[−1,1]}(t)e^{−jt}e^{j401t})$ to find $\ u_{c1}$ but how is this justified if we want to find the output of $\ u_p(t) \cos(401\pi t) $ and not just $\ u_p $ that is just rearranged. Shouldn't the translation induced by the cosine be taken into account. I'd appreciate any help.

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The idea of this exercise is to show what happens if you have a frequency offset at the receiver, i.e. if the actual carrier frequency is different from what the receiver thinks it should be.

You can write the passband signal as

$$u_p(t)=\text{Re}\left(I_{[-1,1]}e^{j400\pi t}\right)\tag{1}$$

Since you're demodulating with a frequency of $\omega_0=401\pi$, it is advantageous to rewrite the passband signal with that reference frequency:

$$u_p(t)=\text{Re}\left(I_{[-1,1]}e^{-j\pi t}e^{j401\pi t}\right)\tag{2}$$

From $(2)$ you can read off the new complex envelop with respect to the actual demodulation frequency $\omega_0=401\pi$:

$$u(t)=u_c(t)+ju_s(t)=I_{[-1,1]}e^{-j\pi t}=I_{[-1,1]}\cos(\pi t)-jI_{[-1,1]}\sin(\pi t)$$

Demodulation with $\cos(401\pi t)$ will give you the I component $u_c(t)$. The factor $1/2$ simply occurs because by multiplying with a cosine you get $u_c(t)\cos^2(\omega_0t)=u_c(t)(\frac12+\frac12\cos(2\omega_0t))$, and the LPF removes the component at $2\omega_0$, which leaves you with $\frac12 u_c(t)$.

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  • $\begingroup$ Thanks for taking the time to answer my question:). In retrospect, I must admit that the question is quite basic and to be honest silly, but at the time I was really confused. But, now things are clearer. $\endgroup$ – user29568 Oct 25 '15 at 14:19
  • $\begingroup$ @user29568: Great that things have become clearer. The question is indeed basic, but not silly. Your confusion was palpable though ... :) BTW, I think that you chose the right book. $\endgroup$ – Matt L. Oct 25 '15 at 14:25
  • $\begingroup$ What a coincidence. I was just about to type this: "Another question: in your experience, what is the best book to learn communication systems from? My course book is the one by simon haykin.". Are you referring to the madhow intro to communication systems? $\endgroup$ – user29568 Oct 25 '15 at 14:27
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    $\begingroup$ @user29568: Yes, I was referring to Madhow, from which your example was taken. I haven't worked through Haykin's book, so I can't say much about it. If it's used in your course I guess you at least need to read it, next to other literature, such as Madhow. $\endgroup$ – Matt L. Oct 25 '15 at 14:30
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    $\begingroup$ @user29568: You could also take a look at Barry, Lee and Messerschmitt's book, which I quite liked. As for my music "career", if you go to my profile on music.SE, you can find a link to my website. $\endgroup$ – Matt L. Oct 25 '15 at 14:51

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