Fourier Series Proof

I want to ask Question about the Fourier series in continuous time domain while reading a book signals and systems Alan Oppenheim. I have confusion in understanding the statement on page 189 of its 2nd edition.
To derive alternative form of Fourier series, we first rearrange the summation in Eq.3.25 as $$x(t) = \sum^{+\infty}_{k\ =\ 1} [a_k e^{jk\omega_0t}+a_{-k} e^{-jk\omega_0t}]$$

where Eq. 3.25$$x(t) = \sum^{+\infty}_{k\ =\ -\infty} a_k e^{jk\omega_0t}$$ I want to know two things
1) How summation from -infinity to +infinity changes to 1 to +infinity

2) How we get this term $$a_{-k} e^{-jk\omega_0t}$$ in the equation.

You just need to split the sum into the positive and the negative indices (without forgetting the index $k=0$):
$$x(t)=a_0+\sum_{k=1}^{\infty}a_ke^{jk\omega_0 t}+\sum_{k=-\infty}^{-1}a_ke^{jk\omega_0 t}\tag{1}$$
By simply changing the sign of the index $k$ in the second sum in $(1)$ you get
\begin{align}x(t)&=a_0+\sum_{k=1}^{\infty}a_ke^{jk\omega_0 t}+\sum_{k=1}^{\infty}a_{-k}e^{-jk\omega_0 t}\\&= a_0+\sum_{k=1}^{\infty}\left[a_ke^{jk\omega_0 t}+a_{-k}e^{-jk\omega_0 t}\right]\end{align}\tag{2}
• @AadnanFarooqA: No, you just change the sign both in the sum and in elements over which you sum: e.g., $\sum_{k=-2}^{-1}f_k=\sum_{k=1}^2f_{-k}=f_{-2}+f_{-1}$ Oct 5 '15 at 13:06