I have a digital signal that was made from analog one by staggering sampling rate:

$\tau_i = \begin{cases}\tau_{even}& \text{if } i = 2n\\ \tau_{odd} & \text{if } i = 2n+1\end{cases}$

And I have a simple correlative filter, for example, smoothing filter

[1, -2, 1]

How should I calculate frequency response of such a filter?

  • $\begingroup$ Has the analog signal been bandlimited before sampling? $\endgroup$
    – Jazzmaniac
    Commented Jul 14, 2015 at 17:56

2 Answers 2


I know this is an old question, but @Jdip answers it directly in this answer to my related question. I'll quote directly from his answer:

Digital Spectra Of Non-Uniformly Sampled Signals : Theories and Applications is a somewhat obscure reference (from 1988! can't go wrong!) that gives a general representation of the spectrum of a special case of non-uniformly sampled digital signals: periodically non-uniform sampled signal.

He continues with details from the paper:

The paper deals with a special case of non-uniform sampling, Periodically nonuniform sampling, expanding on @Fats32’s answer regarding

sampling instants periodically repeated by blocks of $N$

Periodically nonuniform sampling

It starts with a signal $g(t)$, band-limited to ($-1/2T, 1/2T$), with Fourier transform $G^a(\omega)$:

The signal $g(t)$ is sampled in such a structured way that the sampling time instances [...] have an overall period $MT$.

It then defines another band-limited sequence, $\bar{g}(t)$:

The sampled data sequence is then treated as if it were obtained by sampling another function $\bar{g}(t)$, [...] at uniform rate $1/T$.

and states the aim of the paper (which answers your question, at least for these types of non-uniformly sampled signals):

We are interested in finding the representation of the digital spectrum of $\bar{g}(t)$ in terms of the Fourier transform $G^a(\omega)$ of $g(t)$.

Using the framework described above, it then goes through a really nice derivation of $G(\omega)$ to arrive at two representations, from which you can see the effect of the non-uniform sampling on the spectrum:

$$G(\omega) = \frac{1}{MT} \sum_{m=0}^{M-1}\left[\sum_{k=-\infty}^{\infty}G^a\left[\omega-k(\frac{2\pi}{MT})\right]e^{j[\omega-k(\frac{2\pi}{MT})]t_m}\right]e^{-jm\omega T} \tag{2}$$

And re-writing (2) with $t_m = mT - r_mT$, $r_m$ being the ratio of $mT - t_m$ to the average sampling period $T$ gives (4):

$$G(\omega) = \frac{1}{T}\sum_{k=-\infty}^{\infty}\left( \frac{1}{M}\sum_{m=0}^{M-1}e^{-j\left[\omega-k(\frac{2\pi}{MT})\right]r_mT}e^{-jkm(\frac{2\pi}{M})}\right)G^a\left[\omega-k(\frac{2\pi}{MT})\right] \tag{4}$$


Relevant, Synchrosqueezing-based Recovery of Instantaneous Frequency from Nonuniform Samples. The main result is that SSQ beats traditional bandlimited reconstruction approaches for a certain class of random sampling instant perturbations.

Filtering is achieved by manipulating the transform, followed by inversion. SSQ is implemented in Python at ssqueezepy.

  • $\begingroup$ Out of curiosity, what is the class of random sampling perturbations that SSQ is better for? $\endgroup$
    – Gillespie
    Commented Aug 27, 2022 at 20:43
  • 1
    $\begingroup$ @Gillespie WGN?. Not too familiar with the paper. $\endgroup$ Commented Aug 28, 2022 at 14:56

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