1
$\begingroup$

How does SDR resolution translate to audio resolution when using FM demodulation?

For example: using a 8-bit/2.048 Mhz IQ stream, what is the maximum audio sample rate and bit depth that can be generated from a +/-75kHz mono WFM signal with 20kHz audio?

My understanding is that the SDR bit depth is irrelevant but for link quality purposes. But how does the SDR sample rate translate to sample rate and bit depth of the resulting audio signal?

$\endgroup$
  • $\begingroup$ Note: this question has also been posted to the Amateur Radio SE. $\endgroup$ – a CVn May 13 '15 at 8:15
  • $\begingroup$ Please do not cross-post! Let me know if you want me to delete this one, or migrate it to the Ham Radio site. $\endgroup$ – Peter K. May 13 '15 at 8:40
2
$\begingroup$

how does the SDR sample rate translate to sample rate and bit depth of the resulting audio signal?

Extremely indirectly. I haven't got precise mathematical formulas for you, but here's an overview of the topic which should let you figure out where you want to dig deeper.

First of all, FM is an analog modulation. This means that there is no inherent sample rate or bit depth of the signal recovered by demodulating, but only an audio bandwidth and noise floor. So let's look at what influences that:

  • The bits per sample (bit depth) of the digitized RF determines the amount of error introduced by the quantization (conversion to discrete samples), which can be described as quantization noise.

    Note that quantization noise is at a constant level in the digital signal coming from the ADC. This means that — unlike radio interference — the signal-to-quantization-noise ratio improves the more you turn up your receiver's gain. But you can only do that so far before you get clipping (signal level exceeding the representable sample values).

    Therefore, the best results are obtained when you have a narrow analog filter in your receiver to remove all but the desired signal before digitization — the wider bandwidth you receive, the more total power is arriving, and so the less gain you can use before clipping.

    Of course, using a narrow bandwidth prevents you from having those pretty waterfall displays of ten stations at once. It's a tradeoff.

    For more words on the subject, see my previous answer over on Amateur Radio Stack Exchange, to the question Why is dynamic range relevant for an SDR?

  • A simple analysis would suggest that the sample rate of the digitized RF has no effect, because it's just bringing in a wider bandwidth, full of unrelated signals and noise, than we actually need. However, this is not true, if the ADC has fewer bits per sample than the actual DSP processing (for example, 8-bit integer samples from the ADC going into 32-bit floating-point DSP operations). The extra samples contain some of the information that was lost in quantization; resampling the unnecessarily-high-rate signal to a lower rate will automatically use that information, so those 32 bits aren't actually wasted.

    So to combine this with the previous point, the best case given fixed hardware is to configure it (if possible) for the narrowest analog filter bandwidth and the highest sample rate (creating a signal whose spectrum has an obvious filter hump in the middle) and then resampling it before demodulation.

To sum up, the sample rate and bit depth of the incoming RF determines how much noise is added to the signal by the process of digitization. The next question is how that noise, the RF noise entering the software demodulator, affects the noise level of the resulting audio, and I'm afraid I don't know that and haven't found an obvious reference.

Now that we know that our input can be considered as a signal with more or less noise depending on its parameters, let's look at what to do with the output.

  • As Nyquist tells us, the sample rate of the output audio signal does not need to be greater than twice the highest frequency present in the signal. That's the audio bandwidth, which for broadcast FM is, let's say, 15 kHz. Therefore, the required sample rate is 30 kHz, ideally. However, the signal must be filtered to remove noise that is outside the expected bandwidth, and using exactly 30 kHz sample rate means that the noise which passes the necessarily-imperfect filter will be aliased down into lower frequencies. Thus, it is better to use a higher sample rate to allow some room for the filter transition band — perhaps 44.1 or 48 kHz, because those are common audio sample rates.

  • Quantization introduces quantization noise — but we already have noise in our signal. Therefore, the bit depth of the audio should be chosen so that it introduces an insignificant amount of quantization noise compared to the noise already present. (Note: You can't avoid introducing any noise at all. Your finite-precision arithmetic is doing that at every step.)

$\endgroup$
  • $\begingroup$ I appreciate your thorough answer. Unfortunately it doesn't answer the question. I understand that both audio and FM impose their own practical limits on the output frequency range and SNR. But my question is: what do the equations provide? That said, I do appreciate your assurance that downsampling does not detract from the advantage of having a higher sample rate, as clearly that does affect the final output parameters, and my suspicion to that effect is the reason I posted the bandwidth of the WFM signal. $\endgroup$ – NewEndian May 7 '15 at 13:55
  • $\begingroup$ I'm sorry I have to disagree to"it doesn't answer the question";there is no definite answer other than what KevinReid has explained.The question what effective bit depth the resulting audio sample stream has depends not only on a multitude of parameters,including the filters you use to select the FM channel,both in the analog as in the digital domain--as long as you don't figure that one out,you can't have a formula.Then,there's so many ways to go about decoding FM radio signals to audio that no definite answer can be given.To answer your sampling rate question:2.048MS/s oversampled audio. $\endgroup$ – Marcus Müller May 19 '15 at 8:22

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.