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How to solve the initial value problem with

x(n + 1) + x(n) = n^2;
x(0) = 1

I do know how to solve for initial value theorem in differential equation, but not in difference equation.

Please help.Thanks.

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Like a linear constant coefficient ODE the general solution can be written as the sum of a particular solution and the general solution of the homogeneous equation $x(n+1)+x(n)=0$.

Because the right hand side is a polynomial we look for a polynomial particular solution, and a bit of experimenting will show this to be a quadratic:$$x_p(n)=n^2/2-n/2$$

Also the general solution to the homogeneous equation is obviously: $x_h(n)=k(-1)^n$, and the solution to your problem is the sum $x_p(n)+x_h(n)$ with $k$ chosen to satisfy the initial condition.

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