0
$\begingroup$

I'm doing vehicles tracking project. The video is a one-way, no vehicles occlusion. After doing background subtraction, erosion and dilation, I get bounding box objects for each frame, and I can find $centroid(c_x,c_y)$ from that. So, the next thing I want to do is blobs tracking. Here is what I'm thinking on how to do the blobs tracking:

  1. At first frame, store all (cx,cy,id)
  2. Next frame, calculate distance each new (cx,cy) with each of old (cx,cy)
  3. If distance < threshold, update the old (cx,cy) which qualify the formula
  4. If distance > threshold, check if the cx,cy is near the entry coordinate (e.g. around x,y=0-640,0-40), if yes store new (cx,cy).

Is it right and possible to apply to tracking?

Improve this question
$\endgroup$
2
  • $\begingroup$ Looks good. Suggested alternative technique in answer. $\endgroup$
    – Manav Kataria
    Jan 18, 2015 at 2:02
  • $\begingroup$ What if the number of centroids increase or decrease? $\endgroup$
    – Walid Ahmed
    Jan 5, 2017 at 22:03

1 Answer 1

Reset to default
0
$\begingroup$

You might want to consider tracking using MeanShift & Cam Shift:

http://opencv-python-tutroals.readthedocs.org/en/latest/py_tutorials/py_video/py_meanshift/py_meanshift.html#meanshift

Improve this answer
$\endgroup$
4
  • $\begingroup$ Isn't makeshift and camshift is for single tracking, how I can use the technique for vehicles? $\endgroup$
    – user3794938
    Jan 18, 2015 at 10:20
  • $\begingroup$ Can you elaborate on what you mean by 'single tracking'? The example in the link uses Meanshift and CamShift Techniques for vehicle tracking which I believe is your objective. $\endgroup$
    – Manav Kataria
    Jan 18, 2015 at 20:10
  • $\begingroup$ I'm sorry, I'm wrong.. I read some paper and it can tracking multiple objects.. But I'm still don't understand how to do it.. I'm confuse with the mathematics terms.. $\endgroup$
    – user3794938
    Jan 19, 2015 at 5:09
  • $\begingroup$ It sounds good, but how do you get the bounding boxes? $\endgroup$
    – user20881
    May 6, 2016 at 6:23

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge that you have read and understand our privacy policy and code of conduct.

Not the answer you're looking for? Browse other questions tagged or ask your own question.