Suppose two continuous complex domain signals are convolved, how is the magnitude and phase of the resultant signal related to the magnitudes and phase of the original signals?

  • $\begingroup$ If you know that $z(t)=\int_{-\infty}^{\infty}x(\tau)y(t-\tau)d\tau$ then you also know what $|z(t)|$ and $\arg\{z(t)\}$ is. There is no 'simpler' expression for it in general. $\endgroup$ – Matt L. Jul 6 '14 at 11:17
  • $\begingroup$ So, without knowledge of the signals themselves, it is not possible to arrive at a generic relation between them? $\endgroup$ – Manoj Kumar Jul 7 '14 at 9:32
  • $\begingroup$ If you take the magnitude and the phase of the convolution integral, then you have a generic relation, but of course you'll always have the integral. $\endgroup$ – Matt L. Jul 7 '14 at 10:05
  • $\begingroup$ Okay. That's exactly what I wanted to know - whether the integrals can be done away with or not. Thanks! I guess the question is closed. $\endgroup$ – Manoj Kumar Jul 8 '14 at 13:23

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