# Convolving two complex signals - relationship between phase

Suppose two continuous complex domain signals are convolved, how is the magnitude and phase of the resultant signal related to the magnitudes and phase of the original signals?

• If you know that $z(t)=\int_{-\infty}^{\infty}x(\tau)y(t-\tau)d\tau$ then you also know what $|z(t)|$ and $\arg\{z(t)\}$ is. There is no 'simpler' expression for it in general. – Matt L. Jul 6 '14 at 11:17
• So, without knowledge of the signals themselves, it is not possible to arrive at a generic relation between them? – Manoj Kumar Jul 7 '14 at 9:32
• If you take the magnitude and the phase of the convolution integral, then you have a generic relation, but of course you'll always have the integral. – Matt L. Jul 7 '14 at 10:05
• Okay. That's exactly what I wanted to know - whether the integrals can be done away with or not. Thanks! I guess the question is closed. – Manoj Kumar Jul 8 '14 at 13:23