-1
$\begingroup$

sinusoid x(t)=1+sin(2*pi *500) sampling rate :1000 samples/s Can I have 4 points DFT output with the above data.

$\endgroup$
0
$\begingroup$

$ x(t)=1+sin(2*pi *500)$ is a sinusoidal signal with frequency 500 Hz and the sampling rate is 1000 Hz. So you have 1000 samples/sec and 500 cycles/sec.

So you have only 2 samples/cycle. So you can calculate 4 point DFT by taking only 4 values (consecutive) from the samples (Since it represent 2 cycles).

For distortionless DFT you should take atleast one full cycle. Here 2 point DFT also possible. As the number of samples increases the DFT graph become more smooth.

| improve this answer | |
$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.