1
$\begingroup$

I've recently read Herbert Bay's paper of SURF. From which I understand:

  • SURF calculates a table from each image pixel's Hessian matrix's determinant, instead of SIFT's Difference-of-Gaussian table. Then SURF finds local maximal (not extremal) by comparing each determinant to its 8 neighbors in the same scale, and 18 neighbors from 2 nearby scales. Finally, SURF interpolates the maximal point to find the exact position of the point of interest.
  • In the detecting part, SURF uses 9×9 approximations of second-order Gaussian derivatives, combine with an integral image to fast calculate the determinant of each image point's Hessian matrix. The calculation for each derivative of the Hessian matrix is done by placing the correct 9×9 filter center point to an image pixel x, and simply multiplying corresponding points of the filter and the 9×9 sub-image whose point x is the center (points that are off image equal to 0), then calculating the sum of all those multiplications.

Did I take something wrong? Any help is appreciated.

Improve this question
$\endgroup$
3
  • $\begingroup$ It is unclear what your question is and to what do you refer to? Who is they? What is the reference / where did you get this information from? Take your time to derive the background of your question and point out clearly what the actual question is. $\endgroup$
    – Irreducible
    May 15, 2019 at 9:47
  • $\begingroup$ I'm trying to understand how SURF point-of-interest localization works. I'm assuming there are people who read Herbert Bay's paper of SURF that would read this post and help me. Did my question make you hard to understand, even in case you read Bay's paper? $\endgroup$
    – Tung
    May 15, 2019 at 10:04
  • $\begingroup$ You should add this information to your question and make clear where you quote. $\endgroup$
    – Irreducible
    May 15, 2019 at 10:21

1 Answer 1

Reset to default
0
$\begingroup$

You're right.
At the end, SURF was about going around the patents of SIFT by altering some steps yet keeping the same idea.

Improve this answer
$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge you have read our privacy policy.

Not the answer you're looking for? Browse other questions tagged or ask your own question.