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Oct 5 at 10:21 vote accept Balasana
Oct 5 at 10:21 comment added Balasana Thank you for the source code. When looking at it, I more or less immediately found my dumb mistake: I scaled the noise by $\sigma^2 / 2$ instead of $\sigma / \sqrt{2}$.
Oct 4 at 16:26 comment added Balasana Let us continue this discussion in chat.
Oct 4 at 11:12 history edited Royi CC BY-SA 4.0
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Oct 4 at 11:09 comment added Royi @Balasana, Look at github.com/RoyiAvital/StackExchangeCodes in SignalProcessing/Q76644/Q76644C.m. I will update the answer.
Oct 4 at 10:48 comment added Balasana You mean the MATLAB snippet of the Steven Kay algorithm!? I also have to try this. - I still suspect that I am doing something wrong, maybe when converting SNR to noise variance or something.
Oct 4 at 10:38 comment added Royi @Balasana, Have you looked at the code from the link I posted? For me they collide perfectly with the CRLB I wrote.
Oct 4 at 10:32 comment added Balasana Yes, of course. This was just a toy example. However, the CRB for known and for unknown phase have the same slope on a log scale. They would just be shifted up or down. So that would not explain, why the MSE curve of the ML estimator (and as I tried also of the MUSIC estimator) has, on a log scale, a steeper negative slope than the CRB. Or at least, I do not see it.
Oct 4 at 10:24 comment added Royi I don't think in real world you expect to know the phase :-).
Oct 4 at 10:18 comment added Balasana According to the publication mentioned above, this is the CRB for the case that the phase in unknown. However, in my case the phase is known (i.e., zero). I also tried the derivation on my own and also came more or less to the same CRB (a different constant factor of: 3 instead of 6; see the Q variable in the paper.).
Oct 4 at 5:59 history answered Royi CC BY-SA 4.0