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Feb 7 at 17:00 comment added Ben Shaines Oh I see, thanks! sorry for the confusion
Feb 7 at 14:18 comment added Marcus Müller @BenShaines no, you din't get that right. Ahsan nowhere says that boundedness in the Y axis is relevant to whether it's bandlimited. Ahsan says that the concetration around $\omega=0$ is what counts for bandlimitation.
Feb 7 at 9:20 comment added Ben Shaines Hi, thanks for the explanation. Regarding the bandwidth, so you say the signal is indeed bandwidth-limited, but not perfected since its Fourier transform is not bounded from $Y$ axis. Did I understand correctly?......... Regarding the energy, yea...... regarding the incorrect, I understand what you say, but basically, according to definition, it is $\infty$, so I really am troubled now :\...............
Feb 7 at 9:14 history answered Ahsan Yousaf CC BY-SA 4.0