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I doubt the optimal a is ${\mu^2/(\mu^2+\sigma^2/N)}$. It, it seems the result is unsatisfactory. It's It's better to use average.
I doubt the optimal a is ${\mu^2/(\mu^2+\sigma^2/N)}$. It seems the result is unsatisfactory. It's better to use average.
I doubt the optimal a is ${\mu^2/(\mu^2+\sigma^2/N)}$, it seems the result is unsatisfactory. It's better to use average.
I doubt the optimal a is ${\mu^2/(\mu^2+\sigma^2/N)}$.
