Timeline for Is there a stable linear shift invariant system whose transfer function is $H(z) = z^*$
Current License: CC BY-SA 4.0
5 events
| when toggle format | what | by | license | comment | |
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| Jun 10, 2023 at 16:33 | vote | accept | CommunityBot | ||
| Jun 8, 2023 at 2:12 | comment | added | robert bristow-johnson | And that's the answer to my question. I would say it as: But $z^{-1} \neq z^{*}$ for $|z| \ne 1$. | |
| Jun 7, 2023 at 20:45 | comment | added | Ahsan Yousaf | @robertbristow-johnson Write $z$ in polar form: $$z= re^{j\omega}$$ then $$z^{-1}=\frac 1z = \frac 1r e^{-j\omega}$$ The case when $r=1$ is a special case for which the equality holds. | |
| Jun 7, 2023 at 18:56 | comment | added | robert bristow-johnson | //"But $z^{-1} \neq z^{*}$. This is a contradiction!"// - - - - - - - How is that the case? | |
| Jun 7, 2023 at 18:19 | history | answered | Ahsan Yousaf | CC BY-SA 4.0 |